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A concerted substitution

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01 / 04 · Locate the reaction center

Predict firstShould OH⁻ approach the bromine, or the carbon bonded to it?

Preparing the model…
OH⁻ + CH₃Br → CH₃OH + Br⁻ · reaction coordinate sketch
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Guided lesson

Understand the spatial relation between concerted bond making, bond breaking, and backside attack.

Prerequisites: The nucleophile supplies a bonding electron pair; the leaving group takes the original bonding pair with it.
01 / 04

Locate the reaction center

Predict firstShould OH⁻ approach the bromine, or the carbon bonded to it?

The oxygen end of the nucleophile donates its electron pair to the carbon. In CH₃Br the electrons of the C–Br bond finally leave with the departing Br. All position changes here are driven by a teaching reaction coordinate.

How to observe

  • Watch the nucleophile attack from the side opposite the leaving group
  • Pause at the transition state and inspect the two partial bonds and the three in-plane hydrogens
  • Compare the umbrella inversion between the reactant and the product

Model notes

A qualitative reaction path for OH⁻ and CH₃Br forming CH₃OH and Br⁻. The horizontal progress is a reaction coordinate, not real time or a computed minimum-energy path; dashed lines mark partial bonds. The three hydrogens of the methyl group are identical, so this example gives no distinguishable R/S enantiomers even though the geometry inverts.